Nov 22nd, 2021 - Daily Quiz -CSAT 2
1. Three pipes of varying diameters can fill vessels of 2, 4 and 9 litres in 2, 9 and 25 minutes respectively. What is the ration of their diameters? If the speed of flow is found to be same in all three cases?
(a) 3:2:3
(b) 3:4:1
(c) 15:10:9
(d) 9:10:15
2. There are 15 persons seated around a round table. What is the probability that two of them are always together?
(a) 2/15
(b) 2/13
(c) 2/11
(d) None of these.
3. If a merchant offers a discount of 40% on the marked price of his goods and thus ends up selling at cost price, what was the % mark up?
(a) 11.66%
(b) 11.11%
(c) 61.11%
(d) 66.66%
4. A painted wooden cube is cut into twenty seven equal pieces. How many of these small cubes are painted on three sides?
(a) 8
(b) 3
(c) 6
(d) 2
5. Two bags were sold at Rs. 100 each. After selling it was realised that on one, a profit of 10% was made and on other a loss of 10% was made. What is the net gain/loss%?
(a) 1% gain
(b) 1% loss
(c) No loss no gain
(d) 0.1% loss
Answers
| 1. Volume per unit time = Cross section area of pipe x speed of flow.
V/t directly proportional to d2
d12 : d22 : d32 = 2/2 : 4/9 : 9/25 = (1)2 : (2/3)2 : (3/5)2
d1 : d2 : d3 = 1 : 2/3 : 3/5 = 15 : 10 : 9 |
| 2. Probability = 2/14. = 1/7. |
| 3. If the merchant offers a discount of 40% on the marked price, then the goods are sold at 60% of the marked price.
The question further states that when the discount offered is 40%, the merchant sells at cost price.
Therefore, selling @ 40% discount = 60% of marked price (M) = cost price (C)
i.e., a mark up 66.66%. |
| 4. From the drawing there are 8 cubes with 3 colored sides, 12 cubes with 2 colored sides, 6 cubes with 1 colored side and 1 cube (Central one) with no colored sides. We note that 8 + 12 + 6 +1 = 27. The analysis could just as well be done by using the section’s top-middle-bottom or left-middle-right. Note that the symmetry of the cube provides and automatic check on the validity of the number of colored faces.
Note:
If the cube of n*n*n cut into 1*1*1, then
(i) No of cubes no side painted = (n-2)*(n-2)*(n-2) (ii)
No of cubes exactly one side painted = (n-2)*(n-2)*6
(iii) No of cubes exactly two side painted = a= (n-2)*12
No of cubes exactly three side painted = b= 8
No of cubes atleast two side painted = a+b
Using the above formula we have here n=3 and hence
No of cubes no side painted = 1
No of cubes exactly one side painted = 6
No of cubes exactly two side painted = a = 12
No of cubes exactly three side painted = b = 8
No of cubes atleast two side painted = a+b =20 |
| 5. Given Sp of Bag 1 & Bag 2 = 100 each
profit made in Bag 1 is 10% of Cp & loss made in Bag 2 is 10% of Cp
There fore, Cp of Bag 1 is 90.90 Rs, Cp of Bag 2 is 111.11
Total Cp = 90.90 + 111.11 = 202.01
Total Sp = 100 + 100 = 200, therefore net loss is 202.01 – 200 = 2.01 Rs.
Loss % = (2.01/200) x 100 = 1.005% @ (approx) 1% loss. |
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